解决:您当前的访问请求当中含有非法字符

2025-04-18 22:40:20

1、查找代码:private function _xss_check() { static $check = array(&垆杪屑丝#39;"', '>', '<', '\'', '(', ')', 'CONTENT-TRANSFER-ENCODING'); if(isset($_GET['formhash']) && $_GET['formhash'] !== formhash()) { system_error('request_tainting'); } if($_SERVER['REQUEST_METHOD'] == 'GET' ) { $temp = $_SERVER['REQUEST_URI']; } elseif(empty ($_GET['formhash'])) { $temp = $_SERVER['REQUEST_URI'].file_get_contents('php://input'); } else { $temp = ''; } if(!empty($temp)) { $temp = strtoupper(urldecode(urldecode($temp))); foreach ($check as $str) { if(strpos($temp, $str) !== false) { system_error('request_tainting'); } } } return true; }

2、替换为:private function _xss_check() { $temp = strtoupper(urldecode(urldecode($_SERVER['REQUEST_URI']))); if(strpos($temp, '<') !== false || strpos($temp, '"') !== false || strpos($temp, 'CONTENT-TRANSFER-ENCODING') !== false) { system_error('request_tainting'); } return true; }

3、保存后,在论坛后台更新缓存

声明:本网站引用、摘录或转载内容仅供网站访问者交流或参考,不代表本站立场,如存在版权或非法内容,请联系站长删除,联系邮箱:site.kefu@qq.com。
猜你喜欢