编程序：计算某年某月有多少天（区分闰年和闰月）怎么编
源程碌食撞搁序代码如下：
#include <iostream>
using namespace std;
int main()
{
int year, month;//定义年份月份
double a, b, c;//用于判断的变量
cout << "请输入年份 月份：";//文字提示输入年份月份
cin >> year >> month;//输入年份月份
a = year % 4;//能否被4整除
c = year % 100;//能否被100整除
b = year % 400;//能否被400整除
if (((a == 0) && (c != 0)) || (b == 0))//判断
{
switch (month)//大月1357811
case 1:
case 3:
case 5:
case 7:
case 9:
case 11:
{
cout << "本月有31天" << endl;
break;
}
switch (month)//小月4681012
case 4:
case 6:
case 8:
case 10:
case 12:
{
cout << "本月有30天" << endl;
break;
}
switch (month)//判断闰年否
case 2:
{
cout << "本月有29天" << endl;
break;
}
}
else
{
switch (month)//大月1357811
case 1:
case 3:
case 5:
case 7:
case 9:
case 11:
{
cout << "本月有31天" << endl;
break;
}
switch (month)//小月4681012
case 4:
case 6:
case 8:
case 10:
case 12:
{
cout << "本月有30天" << endl;
break;
}
switch (month)//判断闰年否
case 2:
{
cout << "本月有28天" << endl;
break;
}
}
return 0;
}
程序运行结果如下：
扩展资料：
其他实现方法：
#include stdio.h
#include stdlib.h
void main()
{
int year, month, days;
printf(输入年份：);
scanf(%d,year);
printf(输入月份：);
scanf(%d, month);
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
days=31;
break;
case 4:
case 6:
case 9:
case 11:
days=30;
break; case 2:
if(year%4==0 year%100!=0 || year%400==0// 判断闰年
days=29;
else days=28;
break;
default:
printf(月份输入错误！\n);
exit(1);
break; }
printf(天数：%d\n, days);
}